2016
Resultado da Busca
67.Block ‘B’ moves without rotation vertically downwards with constant velocity of 1m/s then what is the relative velocity of C with respect to A :
Block B of mass 2 kg is placed on smooth horizontal plane. Block A of mass 1 kg is placed on block B. The coefficient of friction between A and B is 0.40. The block A is imparted a velocity 16 m/s at t = 0. Find the time at which momentum of the two blocks are equal (in seconds). (g = 10 m/s 2).
Assertion :Block a is moving on the horizontal surface towards right under action of force F. all surfaces are smooth. At the instant shown, the force exerted by block A on block B is equal to net force on block B. Reason: From Newton's third law, the force exerted by block A and B is equal in magnitude to force exerted by block B on A.
Block A of mass 2 k g is placed over a block B of mass 8 k g. The combination is placed on a rough horizontal surface. If g = 10 m s − 2, coefficient of friction between B and floor = 0.5, coefficient of friction between A and B = 0.4 and a horizontal force of 10 N is applied on 8 k g block, then the force of friction between A and B is,
Strings connecting masses A and B with the pulleys are horizontal and all pulleys and strings are light. Friction coefficient between the surface and the block B is 0.2 and between blocks A and B is 0.7. The system is released from rest. Use (g = 10 m/s 2). Find the magnitude of frictional force (in N) between block A and B.
The free-body diagrams for block B and for the knot just above block A are shown below. $$\vec{T_1}$$ is the tension force of the rope pulling on block B or pulling on the knot (as the case maybe), $$\vec{T_2}$$ is the tension force exerted by the second rope (at angle $$\theta = 30^\circ$$) on the knot, $$\vec f$$ is the force of static friction exerted by the horizontal surface on block B ...
Block B moves to the right with a constant velocity v 0. Assuming the pulleys and the surface to be smooth and the string to be inextensible, the velocity of block A relative to block B is View Solution
An object of mass 1.5 kg travelling in a straight line with a velocity of 5 m s − 1 collides with a wooden block of mass 5 kg resting on the floor. This object stickes with wooden block after collision and both move together in a straigt line. Calculate the velocity of the combination of these objects after collision.
A block of mass 10 kg is placed on rough horizontal surface whose coefficient of friction is 0.5. If a horizontal force of 100 N is applied on it, then acceleration of block will be [Take g = 10 ms − 2 ]
Block B has mass m and is released from rest when it is on top of wedge A, which has a mass 3m. Determine the tension in cord CD needed to hold the wedge from moving while B is sliding down A. Neglect friction.
