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Principais notíciasAções relacionadas
Get the range of the required distribution, in this case, max(X, Y) Find the CDF of this distribution as a function of the known distributions Find the PDF of the distribution by differentiating the CDF
21 de ago. de 2011 · M (x) is a function. Taking the maximal number amongst the parameters. max {x1, x2} = {x1, if x1> x2 x2, otherwise. You can define like that the maximum of any finitely many elements. When the parameters are an infinite set of values, then it is implied that one of them is maximal (namely that there is a greatest one, unlike the set {− 1 n ...
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$\begingroup$ I prefer $\max\{f(x_1,\ldots,f(x_n)\}$ with curly braces and no parentheses. In this instance, the parentheses don't actually help, and the curly braces remind you that the thing whose maximum is sought is a set rather than a tuple. $\endgroup$
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20 de mai. de 2021 · As you can see, the result is not, and can no longer be, a negative number (because of the most significant bit, the sign bit, cannot be 1 if we want to represent a positive value) and all other less significant bits are set to one. This represents the value 2,147,483,647, which is the max value of a signed 32-bit number.
19 de set. de 2017 · Since composition of convex functions is convex, we only need to show max (x, y) is convex. But max (x, y) = x + y 2 + | x − y 2 | and | ⋅ | is obviously convex. A function f: Rn → R is convex if and only if its epigraph epif = {(x, t) ∈ Rn × R ∣ f(x) ≤ t} is a convex set.
19. Let X ⊂Rn X ⊂ R n and Y ⊂Rm Y ⊂ R m be compact sets. Consider a continuous function f: X × Y → R f: X × Y → R. Say under which condition we have. minx∈Xmaxy∈Y f(x, y) =maxy∈Y minx∈X f(x, y). min x ∈ X max y ∈ Y f (x, y) = max y ∈ Y min x ∈ X f (x, y). From this we have that maxy∈Y minx∈X f(x, y) ≤minx∈ ...
22 de jan. de 2015 · 10. Your reasoning for the density function of W = max(X, Y) is correct. Apply the same reasoning to find that of the minimum, with minor modification. Vis: Let Z = min(X, Y) such that X and Y are independent and both continuous random variables, with density functions: fX and fY. (And cumulative distributions FX,FY).
4 Answers. Sorted by: 61. It might be of help to sketch the function or write it without the max max. We get. f(x) ={(1 − x)2 0 if x ≤ 1 if x ≥ 1 f (x) = {(1 − x) 2 if x ≤ 1 0 if x ≥ 1. It is easy to work out the derivative everywhere except at x = 1 x = 1. At x = 1 x = 1, work out explicitly from definition.
