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20 de fev. de 2017 · I get a warning because I obviously defined a return type (the ones the subclasses need) but do not return anything. If you declare a non-void return type, you must return something: virtual double getAttributeA() { return 0.0; } virtual int getAttributeB() { return 0; }
31 de mai. de 2023 · 然而，如果在一个非空函数中缺失了return语句，就会引发“no return statement in function returning non-void”（非空函数缺失return语句）的错误。. 这个错误一般出现于当我们定义函数时，我们会在函数头部指明该函数的返回类型（即在函数名之前的类型，例如int、float ...
10 de jan. de 2019 · no return statement in function returning non-void [-Werror=return-type] It seems that I lose a return word in this function. But there is return word in the bottom of the function. In order to solve the problem, I'v added a 'retrun 0' in line 17. It works,but the following code after 'return 0' won't be executed. That is not what I want.
12 de jul. de 2010 · That is, every int returning function returns something back, same should be true for functions that return other types as well. If you don't return explicitly, something which you don't know of is returned. If you are not able to return something at the end of function, try returning void to see if it breaks the code.
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28 de jan. de 2016 · Adding Assert(i < 0); before the final return is also advised: this communicates intention to the next developer to read it (possibly you!), and (in slightly more complex situations) catches logic errors in debug, and has no performance impact on release code.
13 de set. de 2021 · You define your function to return integer, that means you have to have return statement inside the function. Also, you have to have main () function, not main1 () as in your case. Every C/C++ needs function that is called main () and it represent the entry point of the program. Try this code: #include <iostream>. using namespace std; // ATM menu.
